I'm after a regular expression that matches a UK Currency (ie. £13.00, £9,999.99 and £12,333,333.02), but does not allow negative (-£2.17) or zero values (£0.00 or 0).
I've tried to create one myself, but I've got in a right muddle!
Any help greatfully received.
Thanks!
This'll do it (well mostly...)
/^£?[1-9]{1,3}(,\d{3})*(\.\d{2})?$/
Leverages the ^ and $ to make sure no negative or other character is in the string, and assumes that commas will be used. The pound symbol, and pence are optional.
edit: realised you said non-zero so replaced the first \\d with [1-9]
Update: it's been pointed out the above won't match £0.01. The below improvement will but now there's a level of complexity where it may quite possibly be better to test /[1-9]/ first and then the above - haven't benchmarked it.
/^£?(([1-9]{1,3}(,\d{3})*(\.\d{2})?)|(0\.[1-9]\d)|(0\.0[1-9]))$/
Brief explanation:
The more fractions of pence (zero in the above) you require adding to the regex the less efficient it becomes.
Under Unix/Linux, it's not always possible to type in the '£' sign in a JavaScript file, so I tend to use its hexadecimal representation, thus:
/^\\xA3?\\d{1,3}?([,]\\d{3}|\\d)*?([.]\\d{1,2})?$/
This seems to take care of all combinations of UK currency amounts representation that I have come across.
/^\\xA3?\\d{1,}(?:\\,?\\d+)*(?:.\\d{1,2})?$/; Explanation:
You could just make two passes:
/^£\d{1,3}(,\d{3})*(\.\d{2})?$/
to validate the format, and
/[1-9]/
to ensure that at least one digit is non-zero.
This is less efficient than doing it in one pass, of course (thanks, annakata, for the benchmark information), but for a first implementation, just "saying what you want" can significantly reduce developing time.
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