I have a list of strings, all of which have a common property, they all go like this "pp:actual_string"
. I do not know for sure what the substring "pp:"
will be, basically :
acts as a delimiter; everything before :
shouldn't be included in the result.
I have solved the problem using the brute force approach, but I would like to see a clever method, maybe something like regex.
Note: Some strings might not have this "pp:string"
format, and could be already a perfect string, ie without the delimiter.
This is my current solution:
ll = ["pp17:gaurav","pp17:sauarv","pp17:there","pp17:someone"]
res=[]
for i in ll:
g=""
for j in range(len(i)):
if i[j] == ':':
index=j+1
res.append(i[index:len(i)])
print(res)
Is there a way that I can do it without creating an extra list?
Here are a few options, based upon different assumptions.
if s.startswith('pp:'):
s = s[len('pp:'):] # aka 3
:
s = s.split(':', 1)[-1]
s = re.sub('^pp:', '', s)
s = re.match('(?:^pp:)?(.*)', s).group(1)
Whilst regex is an incredibly powerful tool with a lot of capabilities, using a "clever method" is not necessarily the best idea you are unfamiliar with its principles.
Your problem is one that can be solved without regex by splitting on the :
character using the str.split()
method, and just returning the last part by using the [-1]
index value to represent the last (or only) string that results from the split. This will work even if there isn't a :
.
list_with_prefixes = ["pp:actual_string", "perfect_string", "frog:actual_string"]
cleaned_list = [x.split(':')[-1] for x in list_with_prefixes]
print(cleaned_list)
This is a list comprehension that takes each of the strings in turn ( x
), splits the string on the :
character, this returns a list containing the prefix (if it exists) and the suffix, and builds a new list with only the suffix (ie item [-1] in the list that results from the split. In this example, it returns:
['actual_string', 'perfect_string', 'actual_string']
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