I have an array that typically has zero's at the beginning and end (and occasionally in the middle).
I want to fill the zeros with the first value found on the left or right of the array.
array = [0, 0, 0, 1, 3, 5, 0, 4, 2, 0, 0, 0]
I want ideally:
new_array = [1, 1, 1, 1, 3, 5, (5 or 4), 4, 2, 2, 2, 2]
How can I accomplish this?
You can try this:
import numpy as np
array = [0, 0, 0, 1, 3, 5, 0, 4, 2, 0, 0, 0]
# nonzero indices in array
nz = np.nonzero(array)[0]
# add element to a list if nonzero otherwise get its closest nonzero element
[x if x else array[nz[np.argmin(np.abs(i-nz))]] for i, x in enumerate(array)]
>>> [1, 1, 1, 1, 3, 5, 5, 4, 2, 2, 2, 2]
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