Let's say I have a directory named dir
. In that directory, I have these folders and files:
folder1
folder2
folder3
file1.mp4
file2.mkv
file3.mp4
I have a text file named list.txt
, which has these lines:
folder1
file3
I want to delete everything from dir that is not available in the list file. Meaning these will not be deleted:
folder1
file3.mp4
And these will be deleted:
folder2
folder3
file1.mp4
file2.mkv
I have tried:
for f in *; do
if ! grep -qxFe "$f" list.txt; then
....
but this does not provide the result I want. Note that i not all filename have extension on the list.
Another option is to avoid the loop, just save the files in an array. using mapfile
aka readarray
which is a bash4+ feature.
#!/usr/bin/env bash
##: Just in case there are no files the glob will not expand to a literal *
shopt -s nullglob
##: Save the files inside the directory dir (if there are)
files=(dir/*)
##: Save the output of grep in a array named to_delete
mapfile -t to_delete < <(grep -Fvwf list.txt <(printf '%s\n' "${files[@]}"))
echo rm -rf "${to_delete[@]}"
checkout out the output of grep -Fvwf list.txt <(printf '%s\n' "${files[@]}")
Remove the echo
before the rm
if you think the output is correct
cd yourpath/dir/
for f in *; do
if ! grep -Fxq "$f" /path/list.txt; then
rm -r "$f"
else
printf "Exists -- %s \n" ${f}
fi
done
In case you are wondering (as I did) what -Fxq
means in plain English:
F
: Affects how PATTERN is interpreted (fixed string instead of a regex)
x
: Match whole line
q
: Shhhhh... minimal printing
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