username = "peter123"
password = "peTeR"
def check(username, password):
username = username.lower()
password = password.lower()
return password in username
print(check(username, password))
There are couple of ways to solve this problem, this are listed below:
b. "abc" in "xabdcd" => False
def userpass(username, password):
return password.lower() in username.lower()
userpass("pEter32", "PETER")
Find Method: Find method returns a index, if substring is present in string else it returns -1
def userpass(username, password): index = username.lower().find(password.lower()) if index>=0: return True else: return False userpass("pEter32", "PETER")
Index Method This is same as find method, but raises an exception if str not found.
def userpass(username, password): try: index = username.lower().index(password.lower()) return True except: return False userpass("pEter32", "PETER")
lambda name, password: password.lower() in name.lower()
In python3's repl:
>>> pairs = (('peter123', 'PeTeR'),
... ('123Peter', 'PETER'),
... ('123pEtEr123', 'non-peter'))
>>> [(lambda nam, pwd: pwd.lower() in nam.lower())(n, p) for n, p in pairs]
[True, True, False]
(Or simply
>>> [password.lower() in name.lower() for name, password in pairs]
[True, True, False]
)
Try using this:
import re
def nameInPassword(userName, password):
flag = re.search(userName, password, re.IGNORECASE)
if flag == None:
return False
else:
return True
print(nameInPassword('Peter', '123')
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