I have these data in my Mongodb collection:
{_id: xxx1, fieldA: valueA_1, fieldB: valueB_1, fieldC: valueC_1},
{_id: xxx2, fieldA: valueA_1, fieldB: valueB_2, fieldC: valueC_2},
{_id: xxx3, fieldA: valueA_2, fieldB: valueB_3, fieldC: valueC_3},
Is there a Mongodb aggregate operator or such that would return this kind of structure:
{
"valueA_1": [
{_id: xxx1, fieldA: valueA_1, fieldB: valueB_1, fieldC: valueC_1},
{_id: xxx2, fieldA: valueA_1, fieldB: valueB_2, fieldC: valueC_2}
],
"valueA_2": [
{_id: xxx3, fieldA: valueA_2, fieldB: valueB_3, fieldC: valueC_3}
]
}
Right now I am doing a simple Schema.find() and after that I apply a reduce function to the result:
data.reduce(function (map, obj) {
map[obj.fieldA] = map[obj.fieldA] ? [...map[obj.fieldA], obj] : [obj];
return map;
}, {});
I would like to know how can I accomplish this behavior using mongodb\mongoose operators only and also if performances would be better using them instead of the reduce function
Thank you all!
try this
db.collection.aggregate([
{
$group: { // first group by the required fieldA
_id: "$fieldA",
docs: {
$push: "$$ROOT"
}
}
},
{
$group: { // this group to gather all documents in one array 'allDocsInOneArray' of objects
// each object has a key = the value of fieldA, and a value = an array of the docs belong to this fieldA
_id: null,
allDocsInOneArray: {
$push: {
k: "$_id", // the key of the object (should be the value of fieldA, which is the _id now after the first group stage)
v: "$docs" // an array of docs belong to this fieldA
// the object should be in this format { k: '', v: [] } in order to be able to convert the whole array to another object in $arrayToObject operation
}
}
}
},
{
"$replaceRoot": {
"newRoot": {
"$arrayToObject": "$allDocsInOneArray" // convert the array of objects to object with key = k (fieldA), value = v (its docs)
}
}
}
])
you can test it here
hope it helps
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