I am trying to convert an unsigned char
buffer array into a double. Why does this not copy the bytes into the double as they are in the array?
#include <iostream>
#include <string>
int main() {
unsigned char buffer[8] = {63, 240, 0, 0, 0, 0, 0, 0};
double x = *(double*)buffer;
std::cout << x << std::endl;
return 0;
}
I also tried doing this:
#include <iostream>
#include <string>
int main() {
unsigned char buffer[8] = {63, 240, 0, 0, 0, 0, 0, 0};
double x ;
memcpy(&x, buffer, sizeof(double)); //NOW USING MEMCPY
std::cout << x << std::endl;
return 0;
}
I looked at this post here , but it only got the same results. The unsigned chars {63, 240, 0, 0, 0, 0, 0, 0} is the representation of the double number 1
.
It outputs: 3.03865e-319
.
You've got your buffer round the wrong way. It should be:
{0, 0, 0, 0, 0, 0, 240, 63}
(on a little-endian machine using IEEE floating point).
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