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ISO time to Human readable time in python

I am using python. My time format is like

2020-05-23T06:35:11.418279Z #May 23, 2020 at 12:05:11 PM GMT+05:30

I want to convert into human readable time like

23-05-2020 12:05 PM

I tried parser too.But no effect.

Can anyone help me with this?

Thanks in advance:)

See also How do I parse an ISO 8601-formatted date?

Unfortunately, a string as '2020-05-23T06:35:11.418279Z' cannot be parsed directly with the built-in fromisoformat (Python 3.7+) due to the Z . You can use strptime instead, or this workaround , or dateutil's parser. Ex:

from datetime import datetime
import dateutil # Python 3.9+: use zoneinfo instead

s = '2020-05-23T06:35:11.418279Z'

### parsing options
# strptime
dt = datetime.strptime(s, '%Y-%m-%dT%H:%M:%S.%f%z')
# alternatively fromisoformat with replace (most efficient)
dt = datetime.fromisoformat(s.replace('Z', '+00:00'))
# or more convenient and less efficient:
dt = dateutil.parser.parse(s)

# change timezone to Indian Standard Time:
dt = dt.astimezone(dateutil.tz.gettz('Asia/Kolkata'))
# datetime.datetime(2020, 5, 23, 12, 5, 11, 418279, tzinfo=tzfile('Asia/Calcutta'))

s_out = dt.strftime('%Y-%m-%d %I:%M %p')
# '2020-05-23 12:05 PM'  
import datetime, pytz
isodate = '2020-05-23T06:35:11.418279Z'
d = datetime.datetime.fromisoformat(isodate[:-1]).replace(tzinfo=pytz.utc) # we need to strip 'Z' before parsing
print(d.astimezone(pytz.timezone('Asia/Kolkata')).strftime('%d-%m-%Y %I:%M %p'))

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