When I execute this code I'm not getting output and it says local variable might be referenced before assignment. I don't know what it is exactly.
def funct():
try:
no = 2
put = []
if no == 1:
out = 'yes'
put.append(out)
elif no == 2:
out = 'no'
put.append(out)
elif no == 3:
out = 'cant predict'
put.append(out)
except ValueError:
print("Something is wrong")
else:
print("Everything is ok")
put = str(put)[1:-1]
print(put)
return put
Here is a similar question and the answer to it might help you, too:
Local variable might be referenced before assignment - Python
The issue addressed here was that the variable in question was assigned values inside two "if" conditions. These conditions were complementary, but the warning came up because there could be a case when none of the conditions were true and the variable would thus remain uninitialised.
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