I have a list of file names. One of the file names is:
ABC_Earth_FullData_3-4-06.csv
I want a variable that is a substring of the filename with the date in date format only:
3-4-06
I am having trouble using gsub(). So far I've used:
file_date <- gsub(file_name = file_date, pattern = "ABC_Earth_FullData_", replacement = "", fixed = T)
And keep getting this error:
Error in gsub(file_name = file_date, pattern = "ABC_Earth_FullData_", :unused argument (file_name = file_date)
file_name is not a valid gsub argument, have a look at help
?gsub
try:
file_date <- gsub(x=file_name,pattern = "ABC_Earth_FullData_", replacement = "",fixed = T)
An option with str_remove
library(stringr)
str_remove_all(str1, '.*_|\\..*')
#[1] "3-4-06"
str1 <- 'ABC_Earth_FullData_3-4-06.csv'
You can use sub
and backreference:
sub(".*_(.*)\\.csv", "\\1", str1)
[1] "3-4-06"
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