How to covert array of shape n, to n,m

Question

I'm trying convert numpy array of shape (80000,) to (80000,55) I'm having the data like below [[1212,121,121],[12,122,111]] After convert this list of list I'm getting the shape of (2,) but I wanna have shape like (2,3) how to do it.

Answer 1

In [68]: np.array([[1212,121,121],[12,122,111]] )                                                               
Out[68]: 
array([[1212,  121,  121],
       [  12,  122,  111]])
In [69]: _.shape                                                                                                
Out[69]: (2, 3)

If you are getting a shape like (2,), it's probably because some of the nested lists differ in shape. Check the dtype as well as the shape . Look at the array as well.

In [70]: np.array([[1212,121,121],[12,122,111,3]] )                                                             
Out[70]: array([list([1212, 121, 121]), list([12, 122, 111, 3])], dtype=object)

An upcoming version will add a warning:

/usr/local/bin/ipython3:1: VisibleDeprecationWarning: Creating an ndarray from ragged nested sequences (which is a list-or-tuple of lists-or-tuples-or ndarrays with different lengths or shapes) is deprecated. If you meant to do this, you must specify 'dtype=object' when creating the ndarray
  #!/usr/bin/python3