how to find the most frequent in list

Question

I'm a newbie in python, and I need to find the most frequent element in list pdInput and how many elements are the same in the list of mostFreqenNum

    mostFreqenNum = []
    contMostnum = [0]
    
    ContTraining = int(input('How many time You like to Train you input: '))
        for i in range(ContTraining):
            pdInput = int(
                input('Please input your number whatever you want: '))
            mostFreqenNum.append(pdInput)
            for x in mostFreqenNum:
                coutFreqenNum = contMostnum.count(x)

Answer 1

given a list of values inp , you can find the most common like this:

1. using collections.Counter

   from collections import Counter

   most_common = Counter(inp).most_common(1)

output is a tuple with (value, count) inside

2. using sorted

   sorted(inp, key=lambda x: inp.count(x), reverse=True)[0]

output is the most common value in the list

3. using numpy : # note only works with numeric values

   np.argmax(np.bincount(inp))

output is the most common value in the list

4. one more using builtins :

   max(set(inp), key=inp.count)

output is the most common value in the list

5. another using pandas :

   import pandas as pd

   pd.value_counts(inp).index[0]

output is the most common value in the list

Answer 2

Why you dont use the built in module from python, statistics. you can use the module like these:

import statistics
### your input code
mode = statistics.mode(mostFreqenNum)
print(mode)

mode() receive parameter list type. Then you can use the count(). Another example, maybe like these:

>>> import statistics
>>> lists = [2,3,2,2,3,4,5]
>>> mode = statistics.mode(lists)
>>> print(mode)
2
>>> lists.count(2)
3
>>>

Answer 3

I am not sure what you are trying to do exactly, but maybe this could work:

mostFreqenNum = {}
contMostnum = 0
myList = [1, 2, 3, 2, 4, 3, 2, 3, 5, 3]

for i in myList:
    if i in mostFreqenNum:
        mostFreqenNum[i] += 1
    else:
        mostFreqenNum[i] = 1
        
for x in mostFreqenNum:
    if mostFreqenNum[x] > contMostnum:
        contMostnum = mostFreqenNum[x]
        mostFreqKey = x
    else:
        continue

print(f'Most frequent key, {mostFreqKey}, seen {contMostnum} times.')

Answer 4

def Prediction_Model_v3():
alnv3 = [[],[]]
inpv3 = int(input('How many time You like to Train you input V3: '))
for i in range(inpv3):
    pdInpv3 = int(
        input('V3 input number whatever you want: '))
    alnv3[0].append(pdInpv3)
    mdv3 = statistics.mode(alnv3[0])
    if(pdInpv3 == mdv3):
        alnv3[1].append(str(len(alnv3[1])))
    print('numberInput V3: ', alnv3[0])
print('Most Frequent number V3 is ', str(mdv3), ':', str(len(alnv3[1])))
pdtISv3 = (((inpv3-int(len(alnv3[1])))*100)/inpv3)
print('Result of prediction V3 is: ', str(
    mdv3), '=', str(pdtISv3), '%')
alnv3.clear()
return str(pdtISv3)