I have an array that is the result of a SELECT query and would like to check whether a certain value exists in that array.
I tried the following but this does not find the value and always returns that the value does not exist in the array.
I am assuming I am referring wrongly to the array. Can someone show me how to do this right?
My array:
array ( 0 => array ( 'itemName' => 'bandwidth', 'itemType' => 'number', 'itemUnit' => 'mbit', ), 1 => array ( 'itemName' => 'bSize', 'itemType' => 'number', 'itemUnit' => 'sqm', ), 2 => array ( 'itemName' => 'bArea', 'itemType' => 'number', 'itemUnit' => 'sqm', ), )
My PHP:
// ...
$resultC = $stmt->get_result()->fetch_all(MYSQLI_ASSOC);
var_export($resultC);
if(in_array('bandwidth', $resultC)) {
echo 'exists in array';
} else {
echo 'does not exist in array';
}
You may use the combination of array_column
with in_array
for your case.
$resultC = [
0 => ['itemName' => 'bandwidth', 'itemType' => 'number', 'itemUnit' => 'mbit'],
1 => ['itemName' => 'bSize', 'itemType' => 'number', 'itemUnit' => 'sqm'],
2 => ['itemName' => 'bArea', 'itemType' => 'number', 'itemUnit' => 'sqm'],
];
return in_array('bandwidth', array_column($resultC, 'itemName'));
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