How to copy word matching using grep command?

Question

I have 2 files: number1.txt and number2.txt.

cat number1.txt

100 Jan
223 January

cat number2.txt

621 Jan
589 January

I want to join both files to single file each line so the result file like this:

cat result1.txt

100 Jan
621 Jan

cat result2.txt

223 January
589 January

I try to run the bash:

#!/bin/bash

number=`cat number2.txt | awk '{print $2}' | sort | wc -l`
awk '{print $2}' number2.txt > month.txt

for i in $(seq 1 $number);
do
        user=`sed -n "$i p" month.txt`
        cat number1.txt | grep "^$user$" > result$i.txt
        cat number2.txt | grep "^$user$" >> result$i.txt
done

but the result files is empty file. I think the problem in the code grep "^$user$" but I dont know how to solve it.

If I change to grep "$user" , The result is not what I wanted and the result are like this:

cat result1.txt

100 Jan
223 January
621 Jan
589 January

cat result2.txt

223 January
589 January

Please help me to solve my problem.

Answer 1

Your usage of ^ and $ means that the line must consist only of $user , nothing else. If you want the lines ending in $user , do a

grep " $user$" 

instead.

Answer 2

Single grep will give you desired output:

$ grep -hv 'Jan$' number?.txt
223 January
589 January

$ grep -hv 'January$' number?.txt
100 Jan
621 Jan