I have two Lists
say
finalblobfpost1=['ABC/XYZ/16082020/K1_SS_ALM_222222_14082020.txt','ABC/XYZ/16082020/K1_SS_ALM_111111_14082020.txt','ABC/XYZ/15082020/K1_AB_KIL_444444_15082020.txt','ABC/XYZ/15082020/K1_AB_KIL_333333_15082020.txt']
With Same Dates for "K1_SS_ALM"
finalblobfpost2=['ABC/XYZ/15082020/K1_SS_ALM_222222_15082020.txt','ABC/XYZ/16082020/K1_SS_ALM_111111_16082020.txt','ABC/XYZ/15082020/K1_AB_KIL_444444_15082020.txt','ABC/XYZ/16082020/K1_AB_KIL_333333_16082020.txt']
With different Dates from "K1_SS_ALM"
i need to groupby with K1_SS_ALM and K1_AB_KIL (re.findall("\w+/\w+/\d+/(.*?)_\d+_\d+.txt", text))
Mycode so far:
finalblobfpost1=['ABC/XYZ/16082020/K1_SS_ALM_222222_14082020.txt','ABC/XYZ/16082020/K1_SS_ALM_111111_14082020.txt','ABC/XYZ/15082020/K1_AB_KIL_444444_15082020.txt','ABC/XYZ/15082020/K1_AB_KIL_333333_15082020.txt']
keyf = lambda text: (re.findall("\w+\/\w+\/\d+\/(.*?)\_\d+_\d+.txt", text)+ [text])[0].strip()
h=[list(items) for gr, items in groupby(sorted(finalblobfpost1), key=keyf)]
print(h)
Result is -Good-Enough-Expected
[['ABC/XYZ/15082020/K1_AB_KIL_333333_15082020.txt', 'ABC/XYZ/15082020/K1_AB_KIL_444444_15082020.txt'], ['ABC/XYZ/16082020/K1_SS_ALM_111111_14082020.txt',
'ABC/XYZ/16082020/K1_SS_ALM_222222_14082020.txt']]
Code:2
finalblobfpost2=['ABC/XYZ/15082020/K1_SS_ALM_222222_15082020.txt','ABC/XYZ/16082020/K1_SS_ALM_111111_16082020.txt','ABC/XYZ/15082020/K1_AB_KIL_444444_15082020.txt','ABC/XYZ/16082020/K1_AB_KIL_333333_16082020.txt']
keyf1 = lambda text: (re.findall("\w+\/\w+\/\d+\/(.*?)\_\d+_\d+.txt", text)+ [text])[0].strip()
h1=[list(items) for gr, items in groupby(sorted(finalblobfpost2), key=keyf1)]
print(h1)
the result is: Not Expected
[['ABC/XYZ/15082020/K1_AB_KIL_444444_15082020.txt'], ['ABC/XYZ/15082020/K1_SS_ALM_222222_15082020.txt'], ['ABC/XYZ/16082020/K1_AB_KIL_333333_16082020.txt'], ['ABC/XYZ/16082020/K1_SS_ALM_111111_16082020.txt']]
Expected is:
[['ABC/XYZ/15082020/K1_AB_KIL_444444_15082020.txt','ABC/XYZ/16082020/K1_AB_KIL_333333_16082020.txt'],['ABC/XYZ/16082020/K1_SS_ALM_111111_16082020.txt','ABC/XYZ/15082020/K1_AB_KIL_444444_15082020.txt']]
It didn't group the keywords. Is anything wrong with regex or i am doing anything wrong?
Kindly Advise please.
Your list needs to be sorted by the same key function as used in groupby!
try this:
h1=[list(items) for gr, items in groupby(sorted(finalblobfpost2, key=keyf1), key=keyf1)]
Only difference is the key=keyf1
in the call to sorted
Output (same as expected):
[['ABC/XYZ/15082020/K1_AB_KIL_444444_15082020.txt', 'ABC/XYZ/16082020/K1_AB_KIL_333333_16082020.txt'], ['ABC/XYZ/15082020/K1_SS_ALM_222222_15082020.txt', 'ABC/XYZ/16082020/K1_SS_ALM_111111_16082020.txt']]
This is explicitly written in the docs for groupby
:
The operation of groupby() is similar to the uniq filter in Unix. It generates a break or new group every time the value of the key function changes (which is why it is usually necessary to have sorted the data using the same key function ).
try this,
import re
from itertools import groupby
print(
[list(v) for _, v in groupby(finalblobfpost1,
key=lambda x: re.search("\w\d+_\w{2}_\w{3}", x).group())]
)
[['ABC/XYZ/16082020/K1_SS_ALM_222222_14082020.txt', 'ABC/XYZ/16082020/K1_SS_ALM_111111_14082020.txt'], ['ABC/XYZ/15082020/K1_AB_KIL_444444_15082020.txt', 'ABC/XYZ/15082020/K1_AB_KIL_333333_15082020.txt']]
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