Grep AWS S3 command output

Question

When running: aws s3 cp command to upload a file from local to S3 it shows the following output:

upload: ./test.txt to s3://demo-bucket/test.txt

How do I extract only s3://demo-bucket/test.txt string from the command output using grep ?

Answer 1

You can pipe the command to grep as follows:

grep -o 's3:\/\/.*$'
#s3://demo-bucket/test.txt

Note the usage of the -o flag, which tells grep to only return the matched string.

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You may also consider piping to awk :

awk '{print $4}'
#s3://demo-bucket/test.txt

which will print the fourth field of the string.