Not sure how to go about it but what would be the easiest way to map the following values and return a date in output?
values = [2009, 11, 1, 2, 6, 9, 19, 0]
map = ['Year', 'Month', 'Day Of Week', 'Day', 'Hr', 'Min', 'Sec', 'MSec']
output = '2 NOV 2009 06:09:19 UTC'
EDIT:
output preferably a datetime obj and not string. Sorry for the confusion List will always be length of 8 values. and always mapped to the map
index order. So map
and values
will always be 8 and map[0]
should be values[0]
simply unpack the appropriate values from the "values" list into datetime.datetime:
from datetime import datetime, timezone
values = [2009, 11, 1, 2, 6, 9, 19, 0]
dtobj = datetime(*values[:2], *values[3:], tzinfo=timezone.utc)
output = dtobj.strftime('%d %b %Y %H:%M:%S %Z').lstrip('0')
# '2 Nov 2009 06:09:19 UTC'
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