I would like to split columns into two and extract and keep the numbers alone in one column.
df <- data.frame(V1 = c("[1] Strongly disagree", "[2] Somewhat disagree", "[3] Neither", "[4] Somewhat agree", "[5] Strongly agree"))
V1
[1] Strongly disagree
[2] Somewhat disagree
[3] Neither
[4] Somewhat agree
[5] Strongly agree
I tried using the separate
function from tidyr
:
tidyr::separate(df, V1, into = c("Value", "Label"), sep = "] ")
Value Label
[1 Strongly disagree
[2 Somewhat disagree
[3 Neither
[4 Somewhat agree
[5 Strongly agree
I might be able to remove the [
with another function, but I was wondering if I can fix this in one step and wonder if there is another function that does the job.
I am trying to get this in the end
Label Value
Strongly disagree 1
Somewhat disagree 2
Neither 3
Somewhat agree 4
Strongly agree 5
If you are more into base R, here is the base R solution:
df <- data.frame(V1 = c("[1] Strongly disagree", "[2] Somewhat disagree", "[3] Neither", "[4] Somewhat agree", "[5] Strongly agree"))
df$value = as.numeric(regmatches(df$V1, regexpr(r"(\d)", df$V1)))
df$V1 = regmatches(df$V1, regexpr("(?<=] ).*", df$V1, perl=TRUE))
df
#> V1 value
#> 1 Strongly disagree 1
#> 2 Somewhat disagree 2
#> 3 Neither 3
#> 4 Somewhat agree 4
#> 5 Strongly agree 5
Created on 2020-09-05 by the reprex package (v0.3.0)
regmatches
is a base R function, which returns the matched value from the vector, it takes as an input a vector and a regexpr
object.
If the first case ( value
column) \\d
is used to extract the digit. In second case, (?<=] ).*
is used to return anything that matches after ]
,
Try this approach:
library(tidyverse)
#Data
df <- data.frame(V1 = c("[1] Strongly disagree",
"[2] Somewhat disagree",
"[3] Neither",
"[4] Somewhat agree",
"[5] Strongly agree"))
#Mutate
df %>% separate(V1,into = c('V1','V2'),sep = ']') %>%
mutate(V1=gsub("[[:punct:]]",'',V1))
Output:
V1 V2
1 1 Strongly disagree
2 2 Somewhat disagree
3 3 Neither
4 4 Somewhat agree
5 5 Strongly agree
If you want further to have other names you can use rename()
:
#Mutate 2
df %>% separate(V1,into = c('V1','V2'),sep = ']') %>%
mutate(V1=gsub("[[:punct:]]",'',V1)) %>%
rename(Label=V2,Value=V1) %>% select(c(2,1))
Output:
Label Value
1 Strongly disagree 1
2 Somewhat disagree 2
3 Neither 3
4 Somewhat agree 4
5 Strongly agree 5
Another way you can try str_extract
to get the value and str_remove
to get rid of square brackets in the label column.
library(dplyr)
library(stringr)
df %>%
transmute(value = str_extract(V1, "\\d+"),
label = str_remove(V1, "\\[.*\\]"))
# value label
# 1 1 Strongly disagree
# 2 2 Somewhat disagree
# 3 3 Neither
# 4 4 Somewhat agree
# 5 5 Strongly agree
An option with extract
library(tidyr)
library(dplyr)
df %>%
extract(V1, into = c("Value", "Label"), "^\\[(\\d+)\\]\\s*(.*)")
# Value Label
#1 1 Strongly disagree
#2 2 Somewhat disagree
#3 3 Neither
#4 4 Somewhat agree
#5 5 Strongly agree
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