How do I get TimeSpan in minutes given two Dates?

Question

To get TimeSpan in minutes from given two Dates I am doing the following

int totalMinutes = 0;
TimeSpan outresult = end.Subtract(start);
totalMinutes = totalMinutes + ((end.Subtract(start).Days) * 24 * 60) + ((end.Subtract(start).Hours) * 60) +(end.Subtract(start).Minutes);
return totalMinutes;

Is there a better way?

Answer 1

TimeSpan span = end-start;
double totalMinutes = span.TotalMinutes;

Answer 2

Why not just doing it this way?

DateTime dt1 = new DateTime(2009, 6, 1);
DateTime dt2 = DateTime.Now;
double totalminutes = (dt2 - dt1).TotalMinutes;

Hope this helps.

Answer 3

我会这样做：

int totalMinutes = (int)(end - start).TotalMinutes;

Answer 4

See TimeSpan.TotalMinutes :

Gets the value of the current TimeSpan structure expressed in whole and fractional minutes.

Answer 5

double totalMinutes = (end-start).TotalMinutes;

Answer 6

From my point of view I think we can calculate it in this way without using TimeSpan which I describe below :

1. At first we need a function which will subtract our present time and uploaded time value of database time.

    public int GetMinute(int presentMinute, int uploadedMinute) { int result = presentMinute - uploadedMinute; return result; } 

2. Then we need to declare our value from, two different DateTime and then fetch out the value 'Minute' from that.

    DateTime presentDateTime = DateTime.Now; // it is present time (supppose 2019-10-31 02:32:21 ) DateTime uploadedDateTime = databaseValue; // it is database time (suppose 2019-11-03 06:27:23 ) 

3.Then called the above function GetMinute .

    int resultMinute = GetMinute(presentDateTime.Minute, uploadedDateTime.Minute); //only passed the minute
    if (resultMinute > 1)
    {
       return resultMinute + "m";
    }
    else if (resultMinute == 0 && presentDateTime.Hour != uploadedDateTime.Hour) //checking if the hour is not same. 
    {
       return uploadedDateTime.Minute + "m";
    }
    else if (resultMinute < 1)
    {
       int calcuResult = Math.Abs(resultMinute);   //here I change negative value to positive value
       calcuResult = 60 - calcuResult;            
       return calcuResult + "m";
    }
    else
    {
       return "Just now";
    }