Too many initializer values while passing boolean array as function input

Question

Good day everyone. I'm working on this Game of Life problem and trying to pass an array of boolean:(Given)

game({0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0}, 15, 9);

into the function below:(Given)

void game(bool cells[], int size, int num_gen) 

However, I'm getting this error: Too many initializer values C/C++ (146)

I tried to play around and was able to pass in values by declaring the array in the main function:

int main(void) 
{
    int cells[]={0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0};
}

But this is my school assignment, so I'm not supposed to edit any given codes/inputs/functions.

I'm kinda lost now, will appreciate any inputs. Thanks in advance!

Answer 1

void game(bool cells[], int size, int num_gen)

The first parameter of your function is not an array. Sure, you declared the parameter to be an array of unspecified length, but such parameter will be adjusted to be a pointer to element of such array. A function parameter is never an array in C++.

As such, you are attempting to initialise a pointer with a brace-enclosed list of values. There are more than one value, so it's wrong (and the types of the values are also incompatible with a pointer).

You can create an array, and pass a pointer to element of that array:

int cells[]={0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0};
game(cells, std::size(cells), 9);

Answer 2

You can use compound literal for this.

Something like

game((bool []){0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0}, 15, 9);

Answer 3

A list of values in braces is not valid at an expression. What you need is a compound literal :

game((bool []){0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0}, 15, 9);

The syntax that looks like a cast before the braced segment gives you the type. You can also use this syntax for a struct literal.