How to order a comma-separated list

Question

In Oracle, I want to rewrite a column the data like this:

2012AName,2019BName,2017DName,2017CName

It's a group by many year+Name order by year desc and name's first char asc after split ',' result like this

2012AName,2017CName,2017CDName,2019BName

Answer 1

Does this fit to your requirement,

First we split the given string and the aggregate back using listagg and the order by you want.

with input(str)
as
(
select'2012AName,2019BName,2017DName,2017CName' as str 
  from dual
)
select listagg(split,',') 
within group (order by substr(split,1,4),substr(split,5,1))
  from 
(
select regexp_substr(str,'[^,]+', 1, level) split
  from input 
connect by regexp_substr(str, '[^,]+', 1, level) 
 is not null
)