regex matching is unable to select alphanumeric string with spaces in python

Question

I have the following list of expressions in python

LIST1=["AR BR_18_0138249",  "AR R_16_01382649",  "BR 16 0138264", "R 16 01382679" ]

In the above string a few patterns are alpha numeric but there is a space between the two second set of sequences. I expect the following output

  "AR BR_18_0138249"
  "AR R_16_01382649"
  "BR 16 0138264"
  "R 16 01382679" 

I have tried the following code

import regex as re
pattern = r"(\bB?R_\w+)(?!.*\1)|(\bB?R \w+)(?!.*\1)|(\bR?^sd \w+)(?!.*\1)"
for i in LIST1:
rest = re.search(pattern, i)
if rest:
    print(rest.group(1))

I have obtained the following result

BR_18_0138249
R_16_01382649
None
None

I am unable to get the sequences with the spaces. I request someone to guide me in this regard

Answer 1

You can use

\b(B?R(?=([\s_]))(?:\2\d+)+)\b(?!.*\b\1\b)

See the regex demo

Details

• \\b - a word boundary
• (B?R(?=([\\s_]))(?:\\2\\d+)+) - Group 1: an optional B , then R , then one or more sequences of a whitespace or underscore followed with one or more digits (if you need to support letters here, replace \\d+ with [^\\W_] )
• \\b - a word boundary
• (?!.*\\b\\1\\b) - a negative lookahead that fails the match if there are
  • .* - any zero or more chars other than line break chars, as many as possible
  • \\b\\1\\b - the same value as in Group 1 matched as a whole word (not enclosed with letters, digits or underscores).

See a Python re demo (you do not need the PyPi regex module here):

import re
LIST1=["AR BR_18_0138249",  "AR R_16_01382649",  "BR 16 0138264", "R 16 01382679" ]
pattern = r"\b(B?R(?=([\s_]))(?:\2\d+)+)\b(?!.*\b\1\b)"
for i in LIST1:
  rest = re.search(pattern, i)
  if rest:
    print(rest.group(1))

Answer 2

This does the work:

[A-Z]{1,2}\s([A-Z]{1,2}+(?:_[0-9]+)*|[0-9]+(?:\s[0-9]+)*)

This regex gives below output:

AR BR_18_0138249
AR R_16_01382649
BR 16 0138264
R 16 01382679

See demo here