How can I add a list of values to a dictionary where the first element in the list belongs to the first key and so on...?

Question

I have a dictionary which has predefined keys:

{1: None, 2: None, 3: None, 4: None, 5: None, 6: None, 7: None, 8: None}

and a list with numeric values:

[0, 10, 20, 30, 40, 50, 60, 100] 

I want to add these values from the list to the dictionary so that it will look like this:

{1: 0, 2: 10, 3: 20, 4: 30, 5: 40, 6: 50, 7: 60, 8: 100}

How can I add every item from the list to the next key of my dictionary?

Answer 1

You directly use zip on the dict and the list of values, tha make pairs, then ues dict to make mappings from pairs

d = {1: None, 2: None, 3: None, 4: None, 5: None, 6: None, 7: None, 8: None}
v = [0, 10, 20, 30, 40, 50, 60, 100]

res = dict(zip(d, v))

print(res) # {1: 0, 2: 10, 3: 20, 4: 30, 5: 40, 6: 50, 7: 60, 8: 100}

You could find strange to passe the whole dict d to zip but iterating over th dict is same as iterating over its key in fact, the following can have more sense but it does the same

dict(zip(d.keys(), v))

Answer 2

Below is more dynamic solution where you dont have prepare half populated dict

a_list = [0, 10, 20, 30, 40, 50, 60, 100] 
a_dict = {idx+1:val for idx,val in enumerate(a_list)}
print(a_dict)

output

{1: 0, 2: 10, 3: 20, 4: 30, 5: 40, 6: 50, 7: 60, 8: 100}

Answer 3

I have a dictionary which has predefined keys:

{1: None, 2: None, 3: None, 4: None, 5: None, 6: None, 7: None, 8: None}

and a list with numeric values:

[0, 10, 20, 30, 40, 50, 60, 100] 

I want to add these values from the list to the dictionary so that it will look like this:

{1: 0, 2: 10, 3: 20, 4: 30, 5: 40, 6: 50, 7: 60, 8: 100}

How can I add every item from the list to the next key of my dictionary?