Why isn't the code I wrote down working properly?

Question

total_price = 0
sneakers = 36.00

total_price += sneakers

print("Total price is" + " " + str(total_price))

print("Total price is" + " " , total_price) << This one doesn`t work properly. 

Those two statements work like this

Total price is 36.0

('Total price is ', 36.0)

Why is the first and the second different?

Answer 1

use this line for second print

print("Total price is"+" ", total_price, sep='')

since print default to sep=' ' so add extra space while if using + you are concatenating text text in this case (same parameter to printf)

sep is a like a flag passed to print to tell it what character separate different parameters passed to it

Answer 2

This might have to do specifically on python 2. The print syntax on python 2 is

print ...

rather than print(...) in python 3.

So the first one have to do with string concatenation. In your first line of code

"Total price is" + " " + str(total_price)

This will result in a new string of "Total price is" , and " " , and str(total_price) combined. (ie the resulting string is "Total price is 36.0" ). It is equivalent to

x = "Total price is" + " " + str(total_price)
print x

Note that if you insert only a variable between () it will not become a tuple, since tuple needs 2 or more variables. So (x) == x

The second one

("Total price is" + " " , total_price)

is NOT a string concatenation. You used a comma to separate 2 variables. Hence, you inserted two variables and created a tuple, hence results in ('Total price is ', 36.0) .

To make it clear it is equivalent to:

x = ("Total price is" + " ", total_price) #create a tuple
print x

Note that on python 3, this two will print the same output. Since print act more as a function print(...) with arguments.

So, it is not not working properly