Inserting n number of records with T-SQL

Question

I want to add a variable number of records in a table (days)

And I've seen a neat solution for this:

SET @nRecords=DATEDIFF(d,'2009-01-01',getdate())
SET ROWCOUNT @nRecords
INSERT int(identity,0,1) INTO #temp FROM sysobjects a,sysobjects b
SET ROWCOUNT 0

But sadly that doesn't work in a UDF (because the #temp and the SET ROWCOUNT). Any idea how this could be achieved?

At the moment I'm doing it with a WHILE and a table variable, but in terms of performance it's not a good solution.

Answer 1

If you're using SQL 2005 or newer, you can use a recursive CTE to get a list of dates or numbers...

with MyCte AS
    (select   MyCounter = 0
     UNION ALL
     SELECT   MyCounter + 1
     FROM     MyCte
     where    MyCounter < DATEDIFF(d,'2009-01-01',getdate()))
select MyCounter, DATEADD(d, MyCounter, '2009-01-01')
from   MyCte 
option (maxrecursion 0)


/* output...
MyCounter   MyDate
----------- -----------------------
0           2009-01-01 00:00:00.000
1           2009-01-02 00:00:00.000
2           2009-01-03 00:00:00.000
3           2009-01-04 00:00:00.000
4           2009-01-05 00:00:00.000
5           2009-01-06 00:00:00.000
....
170         2009-06-20 00:00:00.000
171         2009-06-21 00:00:00.000
172         2009-06-22 00:00:00.000
173         2009-06-23 00:00:00.000
174         2009-06-24 00:00:00.000

(175 row(s) affected)

*/

Answer 2

You can use a WHILE statement for that:

declare @i int
declare @rows_to_insert int
set @i = 0
set @rows_to_insert = 1000

while @i < @rows_to_insert
    begin
    INSERT INTO #temp VALUES (@i)
    set @i = @i + 1
    end

Answer 3

this is the approach I'm using and works best for my purposes and using SQL 2000. Because in my case is inside an UDF, I can't use ## or # temporary tables so I use a table variable. I'm doing:

DECLARE @tblRows TABLE (pos int identity(0,1), num int) 
DECLARE @numRows int,@i int


SET @numRows = DATEDIFF(dd,@start,@end) + 1
SET @i=1

WHILE @i<@numRows
begin
    INSERT @tblRows SELECT TOP 1 1 FROM sysobjects a

    SET @i=@i+1
end

Answer 4

Overall much faster to double the amount of rows at every iteration

CREATE TABLE dbo.Numbers(n INT NOT NULL PRIMARY KEY)
GO
DECLARE @i INT;
SET @i = 1;
INSERT INTO dbo.Numbers(n) SELECT 1;
WHILE @i<128000 BEGIN
  INSERT INTO dbo.Numbers(n)
    SELECT n + @i FROM dbo.Numbers;
  SET @i = @i * 2;
END; 

I deliberately did not SET NOCOUNT ON, so that you see how it inserts 1,2,4,8 rows

Answer 5

you can use a cross join

select top 100000 row_number() over(order by t1.number)-- here you can change 100000 to a number you want or a variable
from   master.dbo.spt_values t1
       cross join master.dbo.spt_values t2

Answer 6

When you have a pre-built numbers table, just use that:

SELECT *
FROM numbers
WHERE number <= DATEDIFF(d,'2009-01-01',getdate())

There are any number of techniques for building the numbers table in the first place (using techniques here), but once it's built and indexed, you don't build it again.

Answer 7

You could do what PinalDave suggests:

INSERT INTO MyTable (FirstCol, SecondCol)
SELECT 'First' ,1
UNION ALL
SELECT 'Second' ,2
UNION ALL
SELECT 'Third' ,3
UNION ALL
SELECT 'Fourth' ,4
UNION ALL
SELECT 'Fifth' ,5
GO

Answer 8

How about:

DECLARE @nRecords INT

SET @nRecords=DATEDIFF(d,'2009-01-01',getdate())

SELECT TOP (@nRecords)
    ROW_NUMBER() OVER (ORDER BY a.object_id, b.object_id) - 1
FROM sys.objects a, sys.objects b

If you don't want it zero-indexed, remove the " - 1 "

Requires at least SQL Server 2005.