How would I get past this assertion test in Python for trying to find the sum of all the number of views listed in a Dictionary?

Question

How would I get past this assertion test in Python for trying to find the sum of all the number of views? Below is the dictionary I am given, and then below that is assertion test I am trying to pass. I have to create a function that returns something that passes the assertion.

video_reviews = [
    {
        "name": "Cats doing nothing",
        "number_of_views": 450743,
        "reviews": [
            {"name": "Jeb", "review": 5},
            {"name": "Samantha", "review": 2},
            {"name": "Crystal", "review": 3},
        ]
    },
    {
        "name": "All Fail",
        "number_of_views": 1239734,
        "reviews": [
            {"name": "Crystal", "review": 5},
            {"name": "Frank", "review": 3},
            {"name": "Jeb", "review": 3},
        ]
    },
    {
        "name": "Runaway Nintendo",
        "number_of_views": 48343,
        "reviews": [
            {"name": "Samantha", "review": 4},
            {"name": "Bill", "review": 3},
            {"name": "Sarah", "review": 4},
        ]
    },
]

assert total_by_video(video_reviews, "Runaway Nintendo") == 48343
assert total_by_video(video_reviews, "All Fail") == 1239734
assert total_by_video(video_reviews, "Critters") == 0

Answer 1

video_reviews is a list of dictionaries. For a single dictionary d you can get the number of views like this: number_of_views=d["number_of_views"] With that knowledge you can use either a for-loop or list-comprehension to create a list that contains only the numbers.

number_of_views_list = [450743, 1239734, 48343]

Now all you have to do is sum up this list. This can be done by a for-loop as well, or you could make use of the sum function.

Your function would probably look somewhat like this:

def sum_of_views(reviews):
    # TODO create number_of_views_list
    # TODO sum up number_if_views_list
    return result