I've created a fatorial function that would help me calculate the taylor expansion of sine. There are no evident mistakes in my code, but the returned value is wrong. That's my code:
PI = 3.14159265358979323846
def fatorial(n):
fatorial = 1
for i in range(1,n+1,1):
fatorial = fatorial * i
return fatorial
def seno(theta):
n = 1
k = 3
eps = 10**-10
theta = (theta*PI)/180
x = ((-1)**n)*((theta)**k)
y = fatorial(k)
while x/y > eps or x/y < -eps:
theta = theta + (x/y)
n = n + 1
k = k + 2
x = ((-1)**n) * ((theta)**k)
y = fatorial(k)
return theta
You are summing theta in the while-loop and therefore using an adjusted angle for the next elements of the Taylor series. Just add a thetas (for the sum) like so (I have taken the liberty to add some performance improvements, no need to recalculate the full factorial, also calculated first elements explicitly and changed the limit check to avoid recalculations of x/y):
import math
PI = 3.14159265358979323846
def fatorial(n):
fatorial = 1
for i in range(1,n+1,1):
fatorial = fatorial * i
return fatorial
def seno(theta):
n = 1
k = 3
#eps = 10**-10
theta = (theta*PI)/180
thetas = theta # <- added this
x = -theta*theta*theta
y = 6
#while x/y > eps or x/y < -eps:
while k < 14:
thetas = thetas + (x/y) # sum thetas
n = n + 1
k = k + 2
#x = ((-1)**n) * ((theta)**k)
x = ((-1)**(n%2)) * ((theta)**k) # but use the original value for the series
#y = fatorial(k)
y *= k * (k-1)
return thetas # return the sum
if __name__ == '__main__':
print(seno(80), math.sin(8*PI/18))
this results in
0.984807753125684 0.984807753012208
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.