[英]Taylor Series for sine using functions
我创建了一个阶乘函数,可以帮助我计算正弦的泰勒展开。 我的代码没有明显的错误,但是返回的值是错误的。 那是我的代码:
PI = 3.14159265358979323846
def fatorial(n):
fatorial = 1
for i in range(1,n+1,1):
fatorial = fatorial * i
return fatorial
def seno(theta):
n = 1
k = 3
eps = 10**-10
theta = (theta*PI)/180
x = ((-1)**n)*((theta)**k)
y = fatorial(k)
while x/y > eps or x/y < -eps:
theta = theta + (x/y)
n = n + 1
k = k + 2
x = ((-1)**n) * ((theta)**k)
y = fatorial(k)
return theta
您在 while 循环中对 theta 求和,因此对泰勒级数的下一个元素使用调整后的角度。 只需像这样添加一个 thetas(用于总和)(我冒昧地添加了一些性能改进,无需重新计算全阶乘,还明确计算了第一个元素并更改了限制检查以避免重新计算 x/y):
import math
PI = 3.14159265358979323846
def fatorial(n):
fatorial = 1
for i in range(1,n+1,1):
fatorial = fatorial * i
return fatorial
def seno(theta):
n = 1
k = 3
#eps = 10**-10
theta = (theta*PI)/180
thetas = theta # <- added this
x = -theta*theta*theta
y = 6
#while x/y > eps or x/y < -eps:
while k < 14:
thetas = thetas + (x/y) # sum thetas
n = n + 1
k = k + 2
#x = ((-1)**n) * ((theta)**k)
x = ((-1)**(n%2)) * ((theta)**k) # but use the original value for the series
#y = fatorial(k)
y *= k * (k-1)
return thetas # return the sum
if __name__ == '__main__':
print(seno(80), math.sin(8*PI/18))
这导致
0.984807753125684 0.984807753012208
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