Will the following create any zombie process?

Question

int main(int argc, char const *argv[])
{
    fork();
    fork();
    fork();
    exit(0);
}

Can this about code create a Zombie process? if yes how and how many? It would be great if you could elaborate. Also can see process becoming a zombie using ps aux | grep a.out ps aux | grep a.out

Answer 1

No, that won't create any zombie processes. When a process becomes orphaned (because its parent called exit , for example), init adopts it, and init quickly reaps any of its children that die.