Trying to make a post request from one application to another using the same Form Data parameters that the first one received. both application controller currently have same method:
public async Task<ActionResult> TestSet()
{
var inputString = Request.Form["inputString"];
var inputFile = Request.Files[0];
var resultString = await _service.Set(inputString, inputFile.FileName, inputFile.ContentType, inputFile.InputStream);
return new MyJsonResult(new
{
fileName = resultString
});
}
which return json string:
{"fileName": "someFileName.png"}
Trying to make the first method to be something like this
public async Task<ActionResult> TestSet()
{
var inputString = Request.Form["inputString"];
var inputFile = Request.Files[0];
if (!string.IsNullOrEmpty(_redirectUrl))
{
using (var client = new HttpClient())
{
HttpContent content = GetContentSomehow(this.Request); // this i have an issue with
var response = await client.PostAsync(_redirectUrl, content);
var responseString = await response.Content.ReadAsStringAsync();
return new MyJsonResult(responseString);
}
}
var resultString = await _service.Set(inputString, inputFile.FileName, inputFile.ContentType, inputFile.InputStream);
return new MyJsonResult(new
{
fileName = resultString
});
}
This could help to get ByteArrayContent for File only.
And this would probably work to get the non-file parameters into StringContent, but how to get both of them into single Content?
var jsonString = JsonConvert.SerializeObject(Request.Form.ToDictionary());
var content = new StringContent(jsonString, Encoding.UTF8, "application/json");
Solved this issue by cominig StringContent and StreamContent into MultipartFormDataContent
public static MultipartFormDataContent GetMultipartFormData(HttpRequestBase req)
{
var formData = new MultipartFormDataContent();
//formData.Headers.ContentType.MediaType = "multipart/form-data";
foreach (var row in req.Form.ToDictionary())
{
formData.Add(new StringContent(row.Value), row.Key);
}
var file = req.Files[0];
StreamContent fileStreamContent = new StreamContent(file.InputStream);
fileStreamContent.Headers.ContentType = new MediaTypeHeaderValue(file.ContentType);
formData.Add(fileStreamContent, file.FileName, file.FileName);
return formData;
}
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