public class Test {
public static String MakeSequence(int N)
{
int j;
N=5;
for (N=5;N>=1;--N)
{
for(j=1;j<N+1;++j)
{
return MakeSequence(5);
}
}
if (N<1)
{
String x = "";
System.out.println(x.isEmpty());
}
}
}
I want to return the sequence 555554444333221 when N=5 and return an empty string if the input parameter N is less than 1, but I'm not sure how to modify the code I made
Be simple and do not add additional checks:
public static String makeSequence(int N) {
StringBuilder buf = new StringBuilder();
while (N > 0) {
buf.append(String.valueOf(N).repeat(N));
N--;
}
return buf.toString();
}
public class Test {
public static String makeSequence(int n) {
String value = " ";
for (int i = n; i >= 1; --i) {
for (int j = 1; j < i + 1; ++j) {
value+= i;
}
}
return value;
}
public static void main(String[] args) {
final String s = makeSequence(5);
System.out.println(s);
}
}
In your code, you always try to assign 5 instead of considering the value send to the method. Above solution returns the sequence and if the parameter N(in code I use n) is less than 1 then returns the empty string. FYI: As a best practice we start both variable and method names in simple letters.
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