C - How does sizeof() of a function call works?

Question

I have a following line in C:

printf("size of sizeof is %d\n", sizeof(printf("lol!\n")));

Am I getting the size of a function pointer here?

Answer 1

Here, sizeof evaluates the return type of printf . (Here an int )

Answer 2

printf() returns no. of char like "lol." has four character + null char(1) so it will return value 5(an int). And then sizeof() will return sizeof(int) ie 4