SQL Query to find Department whose average salary is greater than 500000 in Single table

Question

This is table employee with following columns and data and I want to find out the designation whose average salary is greater than 500000.

idnew_table, Designation, Name, Salary
'1', 'ABC', 'anubhav', '500001'
'2', 'ABC', 'utsav', '2'
'3', 'HHHH', 'ddd', '1000000'
'4', 'TT', 'dss', '2'

Answer 1

You can use GROUP BY and HAVING as follows:

select designation
  from employees 
 group by designation
 having avg(salary) > 500000

Answer 2

You have to change the type of salary column to INT with CAST(expression AS [data type]) in order to have an AVG result. Also with HAVING in sql you can add a condition.

SELECT designation
FROM employees
GROUP BY designation 
HAVING avg(cast(salary as int)) >500000