Extract image url from html

Question

<div class="col-lg-2 col-md-2 vcenter no-pad-top no-pad-bot">
<img itemprop="image" src="/uploads/images/cache/20955226c5c975c230cb8e1f8cff0e6f1583249561_150_150.png" alt="SPINNEY MOBILE DEVELOPMENT" class="b-lazy pull-left center-block img-responsive b-loaded"></div>

I need to extract image from this particular class only

"/uploads/images/cache/20955226c5c975c230cb8e1f8cff0e6f1583249561_150_150.png"

My code:

url = "https://www.appfutura.com/developers/spinney"
html = urlopen(url).read()
soup = BeautifulSoup(html,"lxml")
soup.prettify()

for link in soup.find_all('img'):
    print(link.get('src'))

how can i Acheive further task? please help

Answer 1

If I understood your question correctly:

When printing img "src" attribute you can check whether it contains "/uploads/images/cache/" or not.

img = soup.find_all('img')

for link in img:
    if "/uploads/images/cache/" in link.get('src'):
         print(link.get('src'))

Answer 2

there is a module called 'webbrowser' which lets you open a url, such as:

import webbrowser
url = "https://www.appfutura.com/developers/spinney"
webbrowser.open(url)

but to DOWNLOAD a url you must import requests

import requests


url = 'https://www.appfutura.com/developers/spinney'
r = requests.get(url, allow_redirects=True)

open('yoururlname.html', 'wb').write(r.content)

if you created a folder with that program, the download will end up in your folder. the program will be just a black screen popping up and closing, and the url will be downloaded