While loop if condition is not met

Question

I want to break out of the loop if y or n is set. In my head this is the way to do it, but it seems to get stuck in the while loop even when 'str1' is set to both n and y.

I have also tried to do: while str1:= "y" or str1 != "n": without luck.

str1 = ""
while not str1 == "y" or not str1 == "n": 
    str1 = input('setting [y/n] => ')
    str1 = str1.lower()

Answer 1

Your condition while str1 != "y" or str1 != "n" is always True , if you enter n it'll be different of y and vice-versa.

You want to stop if both condition aren't met

while str1 != "y" and str1 != "n"

Or easier

while str1 not in "yn":