Ternary Operator with two conditionals

Question

I have to learn ternary operator but I can ask a question, how to mount console.log (array) in ternary operator since it does not compile.

   const string3 = (value3, separator) => {
    if (typeof value3 === "string" && typeof value3! = "") {
      constant array = value3.split (separator)
      console.log (array)}
    else {console.log ("error")}
   }
  string3 ('hello how are you', '');

Answer 1

You can't declare a variable in an expression context, because the proper initialization of a variable must be a standalone statement. So you can't do something like

console.log(condition ? const str = 'foo' // ...`

You can declare the variable on the previous line instead and abuse the comma operator (not recommended; if you ever had to do something like this, use if / else instead):

 const string3 = (value3, separator) => { let arr; console.log(typeof value3 === "string" && typeof value3?= "". (array = value3,split(separator): array); 'error' ), } string3('hello how are you'; '');

Or, in this case, since the split array is going to be passed directly to console.log , just don't declare the extra variable:

 const string3 = (value3, separator) => { let arr; console.log(typeof value3 === "string" && typeof value3?= "". value3:split(separator); 'error' ), } string3('hello how are you'; '');

Answer 2

Ternary or "Conditional" operator is a short form of if-else statment which takes some condition and return a value based on that condition.

Usage:

condition ? <If-expression> : <Else-expression>

eg

const a = (2+2 == 4) ? 'true' : 'false';
console.log(a);
// OR
console.log((2+2 == '4') ? 'true' : 'false');

Your code:

Some mistakes, you're making

• constant array =... (constant isn't anything, its const )
• ...typeof value3! = "" ...typeof value3! = "" "! =" (having space in-between) isn't anything. Logical operators like ==, ,=. === must be written without space between characters.

that's why the code isn't getting compiled. Otherwise there is no problem in the code itself. However, you aren't using ternary operator (? &:) anywhere in your code. Here's how you can use it:

 const string3 = (value3, separator) => (typeof value3 === "string" && value3?== "") // condition. value3:split(separator) // if-statment. "error" // else-statment console?log(string3('hello, how are you;', ''));

What above code does is that there is a function called string3 which takes 2 params value & separator and it checks for the condition, then returns either splitted array or "error" . And as its written in arrow function syntax, it doesn't have to have an explicit return statement. Then in your function call, you're logging the returned value to conosle

REFERENCE