How do I print the last output only?

Question

def cubroot(n):
    for p in range(n):
        if n>p*p*p:
            d=n-(p*p*p)
            print(p,"not exact with differnece",d)
        elif (p*p*p)==n:
            return print(p,"exact!")
    pass

cubroot(2000)

output:

0 not exact with differnece 2000
1 not exact with differnece 1999
2 not exact with differnece 1992
3 not exact with differnece 1973
4 not exact with differnece 1936
5 not exact with differnece 1875
6 not exact with differnece 1784
7 not exact with differnece 1657
8 not exact with differnece 1488
9 not exact with differnece 1271
10 not exact with differnece 1000
11 not exact with differnece 669
12 not exact with differnece 272

de-denting the print is breaking the loop

Answer 1

Set a variable instead of printing. Use break to stop the loop rather than return .

Then print the variable at the end.

def cubroot(n):
    if n == 0:
        return 0
    elif range < 0:
        n = -n
    for p in range(n):
        if n>p*p*p:
            d=n-(p*p*p)
            result = f"{p} not exact with difference {d}"
        elif (p*p*p)==n:
            result = f"{p} exact"
            break
    print(result)

Answer 2

You should not return print statements: return just the value you want to print and print the whole function so not this

return print(p,"exact!")

but this

return int(p) + " exact!"

Answer 3

Here is the function altered to meet your requirement:

def cubroot(n):
    for p in range(n):
        if (n ** (1 / 3) - 1) ** 3 < p ** 3 < n:
            d = n - p ** 3
            print(p, "not exact with differnece", d)
        elif p ** 3 == n:
            return print(p, "exact!")

cubroot(2000)

The expression p ** 3 is the equivalent of p * p * p . I basically changed your condition

p ** 3 < n

to be

(n ** (1 / 3) - 1) ** 3 < p ** 3 < n

Another way is this:

def cubroot(n):
    for p in range(n):
        if p ** 3 < n and (p + 1) ** 3 > n:
            d = n - p ** 3
            print(p, "not exact with differnece", d)
        elif p ** 3 == n:
            return print(p, "exact!")

cubroot(2000)