How to bypass response 503 with python

Question

I am trying to scrape some information for my assignment but return response 503 from https://www.klsescreener.com/v2/stocks/view/3182 .

the code I am using is

headers = {'User-Agent': 'Mozilla/5.0 (Windows NT 6.1) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/41.0.2228.0 Safari/537.36'}
page = requests.get('https://www.klsescreener.com/v2/stocks/view/'+stockcode[x],headers=headers)

is it any other way that I can bypass the response 503?

Answer 1

Please do a curl request on the API in order to check if the API is functional or not, Keeping this in mind 503 is generally the error which means you're not getting anything from the respective URL.