Overload struct default values with Designated Initializers

Question

Is it possible to achieve (at least something similar to) this? I need Designated Initializers for "named arguments" and/or possibility to skip setting of some params (not shown here). And still get this "cascade" default values.

Ideally I need set params of Derived (when instantiate) without knowledge of inheritance (because there should be lets say 5 level of inheritance and its user unfriendly have to know how many inheritances there is... ) Of course knowledge of params name and order is needed.

#include <iostream>

using namespace std;

struct Base
{
    string baseDefault = "Default";
    string label = "Base";
};

struct Derived : public Base
{
    // using Base::baseDefault; // do not help
    using Base::Base;
    string label = "Derived";
};

int main()
{
    Derived d1{.baseDefault="ChangedDefault", .label="NewDerived"};
    Derived d2{};
    Base b1{.label="NewBase"};
    Base b2{};

    cout    << "  d1: " << d1.label << d1.baseDefault
            << ", d2: " << d2.label << d2.baseDefault
            << ", b1: " << b1.label << b1.baseDefault
            << ", b2: " << b2.label << b2.baseDefault << endl;
    /* expect: d1: NewDerived ChangedDefault,
               d2: Derived Default,
               b1: NewBase Default,
               b2: Base Default
    */
    return 0;
}

I try to clarify it:

If no default values needed (or just one for each member), I can do this:

struct Base
{
    string withDefault = "baseDefault";
    string noDefault;
};

struct Derived : public Base
{
    string inDerived; /* no matter with/without default*/
};

int main()
{
    Derived d{{.noDefault="SomeSetting"}, .inDerived="NextSetting"};

    Base b{.nodefault="SomeSetting"};

    return 0;
}

But the problem is: I need to use different default value for /withDefault/ if I constructed /Derived/. So Something like this:

struct Derived : public Base
{
    string withDefault = "useThisAsDefaultHere";
    string inDerived; /* no matter with/without default*/
};

Answer 1

Consider the following, "naive", design:

#include <iostream>

struct Base {
  char const* Base_var1 = "Base_var1";
  char const* Base_var2;
};

struct Derived1 : public Base {
  char const* Base_var1 = "Derived1_var1";
  char const* derived1_var3 = "Derived1_var3";
};

struct Derived2 : public Derived1 {
  char const* derived2_var4 = "Derived2_var4";
  char const* derived2_var5 = "Derived2_var5";
};

Here we have five variables, ending on _var1 , _var2 , _var3 , _var4 and _var5 respectively. Their prefix is the name of the class that they are first defined in. For example, Base defines Base_var1 . Although Derived1 overrides the default, it still has the same name in Derived1 of course.

We can thus state that _var1 has a default in Base that is overridden in Derived1 . _var2 has no default, _var3-5 are introduced, with defaults, in Derived1 and Derived2 respectively.

If now we want to construct an object of type Derived2 where we want to use all default values, except for _var3 and _var5 (and of course give _var2 a value) then we could attempt to do this as follows:

int main()
{
  Base b = { .Base_var2 = "main_var2" };
  Derived1 d1 = { b, .derived1_var3 = "main_var3" };
  Derived2 d2 = { d1, .derived2_var5 = "main_var5" };

  std::cout <<
    d2.Base_var1 << ", " <<
    d2.Base_var2 << ", " <<
    d2.derived1_var3 << ", " <<
    d2.derived2_var4 << ", " <<
    d2.derived2_var5 << std::endl;
}

This has several flaws . The most important one is that it isn't correct C++. When we try to compile this with clang++ we get:

>clang++ -std=c++20 troep.cc 
troep.cc:21:22: warning: mixture of designated and non-designated initializers in the same initializer list is a C99 extension [-Wc99-designator]
  Derived1 d1 = { b, .derived1_var3 = "main_var3" };
                     ^~~~~~~~~~~~~~~~~~~~~~~~~~~~
troep.cc:21:19: note: first non-designated initializer is here
  Derived1 d1 = { b, .derived1_var3 = "main_var3" };
                  ^
troep.cc:22:23: warning: mixture of designated and non-designated initializers in the same initializer list is a C99 extension [-Wc99-designator]
  Derived2 d2 = { d1, .derived2_var5 = "main_var5" };
                      ^~~~~~~~~~~~~~~~~~~~~~~~~~~~
troep.cc:22:19: note: first non-designated initializer is here
  Derived2 d2 = { d1, .derived2_var5 = "main_var5" };
                  ^~
2 warnings generated.

And the output of the program is:

Derived1_var1, main_var2, main_var3, Derived2_var4, main_var5

which is the desired result.

With clang++ you only get a warning, but with g++ for example, it won't compile and you get the errors:

>g++ -std=c++20 troep.cc
troep.cc: In function ‘int main()’:
troep.cc:21:22: error: either all initializer clauses should be designated or none of them should be
   21 |   Derived1 d1 = { b, .derived1_var3 = "main_var3" };
      |                      ^
troep.cc:22:23: error: either all initializer clauses should be designated or none of them should be
   22 |   Derived2 d2 = { d1, .derived2_var5 = "main_var5" };
      |                       ^

The second problem is that Derived1 isn't really overriding the value of Base::Base_var1 but instead is hiding it. If it would be passed to a function that takes a Base& then Base_var1 would have an "unexpected" value.

The way I solved the first problem is by splitting the structs into *Ext (extension) structs that define the variables and (initial) defaults, and use classes without member variables for the inheritance. This way you don't run into the need to use a mixture of designated and non-designated:

struct Base {
  char const* Base_var1 = "Base_var1";
  char const* Base_var2;
};

struct Derived1Ext {
  char const* derived1_var3 = "Derived1_var3";
};

struct Derived2Ext {
  char const* derived2_var4 = "Derived2_var4";
  char const* derived2_var5 = "Derived2_var5";
};

class Derived1 : public Base, public Derived1Ext {
};

class Derived2 : public Base, public Derived1Ext, public Derived2Ext {
};

Initialization of Derived2 then becomes:

  Derived2 d2 = {
    { .Base_var2 = "main_var2" },
    { .derived1_var3 = "main_var3" },
    { .derived2_var5 = "main_var5" }
  };

which has extra braces, but is over all rather clean - and you still only have to specify values that you want to differ from the defaults.

Of course, this still lacks the override of the default of Base_var1 .

But we can compile this without errors or warnings;). The output is then

Base_var1, main_var2, main_var3, Derived2_var4, main_var5

The last step is to fix the first value here, without changing main() again.

The only way I could think of is by using magic values... In the above case we only have char const* but in general this could become rather elaborate. Nevertheless here is something that does the trick:

#include <iostream>
#include <cassert>

char const* const use_default = reinterpret_cast<char const*>(0x8);     // Magic value.

struct BaseExt {
  char const* Base_var1 = use_default;
  char const* Base_var2 = use_default;
};

struct Base : BaseExt {
  void apply_defaults()
  {
    if (Base_var1 == use_default)
      Base_var1 = "Base_var1";
    // Always initialize Base_var2 yourself.
    assert(Base_var2 != use_default);
  }
};

struct Derived1Ext {
  char const* derived1_var3 = use_default;
};

struct Derived1 : BaseExt, Derived1Ext {
  void apply_defaults()
  {
    if (Base_var1 == use_default)
      Base_var1 = "Derived1_var1";      // Override default of Base!
    if (derived1_var3 == use_default)
      derived1_var3 = "Derived1_var3";
    BaseExt* self = this;
    static_cast<Base*>(self)->apply_defaults();
  }
};

struct Derived2Ext {
  char const* derived2_var4 = use_default;
  char const* derived2_var5 = use_default;
};

struct Derived2 : BaseExt, Derived1Ext, Derived2Ext {
  void apply_defaults()
  {
    if (derived2_var4 == use_default)
      derived2_var4 = "Derived2_var4";
    if (derived2_var5 == use_default)
      derived2_var5 = "Derived2_var5";
    BaseExt* self = this;
    static_cast<Derived1*>(self)->apply_defaults();
  }
};

int main()
{
  Derived2 d2 = {
    { .Base_var2 = "main_var2"},
    { .derived1_var3 = "main_var3" },
    { .derived2_var5 = "main_var5" },
  };
  d2.apply_defaults();

  std::cout <<
    d2.Base_var1 << ", " <<
    d2.Base_var2 << ", " <<
    d2.derived1_var3 << ", " <<
    d2.derived2_var4 << ", " <<
    d2.derived2_var5 << std::endl;
}

EDIT: Improved version

Instead of the use_default magic number you can use std::optional . And instead of having to call apply_defaults manually, you can add an other member ( dummy ) that does this for you. By adding the [[no_unique_address]] this addition is (probably) completely optimized away (the size of the struct does not increase (the use of std::optional DOES make the struct increase, of course)).

#include <iostream>
#include <optional>
#include <cassert>

//------------------------------------------------------------------------
// Base
struct BaseExt {
  std::optional<char const*> Base_var1 = std::optional<char const*>{};
  std::optional<char const*> Base_var2 = std::optional<char const*>{};
};

struct Base;
struct BaseApply { BaseApply(Base&); };
struct Base : BaseExt {
  void apply_defaults()
  {
    if (!Base_var1)
      Base_var1 = "Base_var1";
    // Always initialize Base_var2 yourself.
    assert(Base_var2);
  }
  [[no_unique_address]] BaseApply dummy{*this};
};
BaseApply::BaseApply(Base& base) { base.apply_defaults(); }

//------------------------------------------------------------------------
// Derived1
struct Derived1Ext {
  std::optional<char const*> derived1_var3 = std::optional<char const*>{};
};

struct Derived1;
struct Derived1Apply { Derived1Apply(Derived1&); };
struct Derived1 : BaseExt, Derived1Ext {
  void apply_defaults()
  {
    if (!Base_var1)
      Base_var1 = "Derived1_var1";      // Override default of Base!
    if (!derived1_var3)
      derived1_var3 = "Derived1_var3";
    BaseExt* self = this;
    static_cast<Base*>(self)->apply_defaults();
  }
  [[no_unique_address]] Derived1Apply dummy{*this};
};
Derived1Apply::Derived1Apply(Derived1& derived1) { derived1.apply_defaults(); }

//------------------------------------------------------------------------
// Derived2
struct Derived2Ext {
  std::optional<char const*> derived2_var4 = std::optional<char const*>{};
  std::optional<char const*> derived2_var5 = std::optional<char const*>{};
};

struct Derived2;
struct Derived2Apply { Derived2Apply(Derived2&); };
struct Derived2 : BaseExt, Derived1Ext, Derived2Ext {
  void apply_defaults()
  {
    if (!derived2_var4)
      derived2_var4 = "Derived2_var4";
    if (!derived2_var5)
      derived2_var5 = "Derived2_var5";
    BaseExt* self = this;
    static_cast<Derived1*>(self)->apply_defaults();
  }
  [[no_unique_address]] Derived2Apply dummy{*this};
};
Derived2Apply::Derived2Apply(Derived2& derived2) { derived2.apply_defaults(); }

//------------------------------------------------------------------------
int main()
{
  Derived2 d2 = {
    { .Base_var2 = "main_var2"},
    { .derived1_var3 = "main_var3" },
    { .derived2_var5 = "main_var5" },
  };

  std::cout <<
    *d2.Base_var1 << ", " <<
    *d2.Base_var2 << ", " <<
    *d2.derived1_var3 << ", " <<
    *d2.derived2_var4 << ", " <<
    *d2.derived2_var5 << std::endl;
}

This prints as output:

Derived1_var1, main_var2, main_var3, Derived2_var4, main_var5
^^^^^^^^^^^^^  ^^^^^^^^^  ^^^^^^^^^  ^^^^^^^^^^^^^  ^^^^^^^^^
Base_var1,     Base_var2  derived1_var3             derived2_var5
default by                           derived2_var
Derived1.                            default by
                                     Derived2.