I am trying to run a while true
loop in python to check if the word I want is same as that in a specific cell of the dataframe I have. I tried in two ways. First one is as below:
while True:
try:
df1 = pd.read_csv(io.StringIO(dfs[4].to_csv(index=False)), skiprows=1, header=[0,1])
c = df1.iat[1,3]
print(c)
if (c == "Margaret"):
df1.to_csv("break.csv", mode='a', header=False)
print("Margaret found")
break
except Exception as e:
print("waiting...")
continue
break
But when the value is not available, instead of trying again, it keeps printing "waiting..." endlessly.
Then I tried like following:
while True:
try:
df1 = pd.read_csv(io.StringIO(dfs[4].to_csv(index=False)), skiprows=1, header=[0,1])
c = df1.iat[1,3]
print(c)
if (c == "Margaret"):
df1.to_csv("break.csv", mode='a', header=False)
print("Margaret found")
break
except:
if c:
print("waiting...")
c = False
continue
But here, when the value is not available, instead of trying again, it automatically skips to next part of the code without even printing "waiting...". Please suggest how I can modify the code. I am a beginner in coding. So will be very thankful if it is explained in a simple manner. TIA
There are somethings to do:
Final code:
try:
df1 = pd.read_csv(io.StringIO(dfs[4].to_csv(index=False)), skiprows=1, header=[0,1])
c = df1.iat[1,3]
print(c)
if (c == "Margaret"):
df1.to_csv("break.csv", mode='a', header=False)
print("Margaret found")
break
except Exception as e:
print("waiting...")
continue
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