std::array template function

Question

I have a simple function to shuffle elements in an std::array

template <typename T, uint size>
void Shuffle(std::array<T, size> &arr) {
    for (uint i = 0; i < arr.size() - 1; i++)
    {
        std::swap(arr[i], arr[Random(i, arr.size())]);
    }
}

make/g++ doesn't like the way I'm declaring this, giving the error "variable or field Shuffle declared void." From what I've found, this is probably an irrelevant error message, but I can't figure out what's actually wrong here.

Answer 1

uint doesn't match the type of the 2nd template parameter of std::array , which is std::size_t . This causes template argument deduction failing when calling Shuffle , unless you specify template arguments explicitly.

You should declare the 2nd template parameter with type std::size_t . eg

template <typename T, std::size_t size>
void Shuffle(std::array<T, size> &arr)