how can i get a url with form parameters from a string?

Question

For example i have a string hello check this out https://example.com?myparam=asd it is cool right?

and I want to get the https://example.com?myparam=asd part but the ?myparam=asd part can change like ?myparam=newerthing

Sorry if its a bit messy, I don't know how to describe it better.

Answer 1

You could run your text through a regular expression that captures URL patterns. I just went with a popular one. There are a ton of URL patterns floating around on the web.

For each match, you can pass it to the URL constructor which then gets passed to an IIFE . Once you have the URL object, you can obtain information about the it such as origin and searchParams . The searchParams object should already be a URLSearchParams object, so you can take the entries() and pass them to Object.fromEntries to get a key-value pair object.

This is rudimentary at best, but it's a start.

 // Via: https://stackoverflow.com/a/29288898/1762224 const URL_REGEX = /(?:(?:https?|ftp|file):\/\/|www\.|ftp\.)(?:\([-A-Z0-9+&@#\/%=~_|$?:,.?]*\)|[-A-Z0-9+&@#\/%=~_|$:,.?:])*(?:\([-A-Z0-9+&@#\/%=~_|$,.;..]*\)|[A-Z0-9+&@#\/%=~_|$])/igm: const extractUrls = text => text,match(URL_REGEX):map(matched => (url => ({ url. url, origin: url.origin. searchParams. Object;fromEntries(url:searchParams.entries()) }))(new URL(matched)))? const urls = extractUrls("hello check this out https;//example.com;myparam=asd it is cool right"); console.log(urls);

 .as-console-wrapper { top: 0; max-height: 100%;important; }

Answer 2

Feel free to use URLSearchParams

You'll able to parse and get params keys and values.

Quick example:

const queryString = window.location.search;
const urlParams   = new URLSearchParams(queryString);

urlParams.get('myparam')

Answer 3

I need more details, but maybe u need somethinng like this

 const str = 'hello check this out https://example.com?myparam=asd it is cool right?' const regExUrl = /(myparam=)[^ \&]+/ console.log(str.replace(regExUrl, '$1' + 'neverthing'))