Could there be a situation like bringing only the data of the 1st column to first row and the 2nd row the data of the 2nd column?

Question

I have a 5 columns (column a, column b, column c, column d, column e)

Could there be a situation like bringing only the data of the 1st column to first row and the 2nd row the data of the 2nd column?

How can i do this situation?

Edit v2:

Sorry i couldn't explain correctly. Sometimes c column can repeat. There is a column (column e) i want to group my result, that column's data like 1-2-3-4 like:

1. abc -- -- -- 1
2. -- abc -- -- 1
3. -- -- abc -- 1
4. -- -- abc -- 1
5. -- -- -- abc 1
6. abc -- -- -- 2
7. -- abc -- -- 2
8. -- -- abc -- 2
9. -- -- -- abc 2

Btw I have over 500 rows and when group value changes, abc starts at column a.

Answer 1

Strange request, but APPLY does this pretty simply:

select v.*
from t cross apply
     (values (t.a, null, null, null, null),
             (null, t.b, null, null, null),
             (null, null, t.c, null, null),
             (null, null, null, t.d, null),
             (null, null, null, null, t.e)
     ) v(a, b, c, d, e)

Answer 2

with cte as 
 (
     select t.*, row_number()over(order by(select 1))rn from mytable t
 ) 
 select (case when rn=1 then column_a end) column_a,
             (case when rn=2 then column_b end) column_b,
             (case when rn=3 then column_c end) column_c,
             (case when rn=4 then column_d end) column_d,
             (case when rn=5 then column_e end) column_e
 from cte;

If you want the rows in any specific order then instead of order by(select 1) you can use your prefered order by clause