Why while loop is filling only the first condition?

Question

while loop give result back when one of the condition succeed, i need both of them, any help

#include <stdio.h>

int   yRechner()
{  
   
    int x = 2;
    int y =0;
    int i =0;
    char answer[2];

    while (i < 1 && y <= x)
    {
        printf("is the wall here pleas answer yes(Y/y) or No(N/n) \n");

        scanf("%s", &answer);

        if (answer[0] == 'N' || answer[0] == 'n')
        {
            printf("one step \n");
            y++;
        }
        else if (answer[0] == 'Y' || answer[0] == 'y')
        {
            if (i < 1 && y > x)
            {
                i++;
                printf("rotate \n");
            }
            else
            {
                printf("am not seeing the wall please say no. \n");
            }
        }
        else
        {
            printf("wrong answer \n");
        }
    }

    return y;
}

int main()
{

    int y = yRechner();
    printf("y = %d\n", y);

    return 0;
}

Answer 1

It isn't apparent whether these conditions, i < 1 and y <= x , are negated or not. In general, if you want to loop while not both of the conditions are true, !(c1 && c2) , you can use De Morgan's laws to simplify !c1 || !c2 !c1 || !c2 .

Answer 2

I found a Solution, thx for your hints

#include <stdio.h>

int   yRechner()
{  
   
int x = 2;
int y =0;
int i =0;
char answer[2];

while (i < 1 )
{
    printf("is the wall here please answer yes(Y/y) or No(N/n) \n");

    scanf("%s", &answer);

    if (answer[0] == 'N' || answer[0] == 'n')
    {
        printf("one step \n");
        y++;
    }
    else if (answer[0] == 'Y' || answer[0] == 'y')
    {
        if (i < 1 && y > x )
        {
            i++;
            printf("rotate \n");
            continue;
        }
        else if (i < 1 && y < x)
        {
            printf("am not seeing the wall please say no. \n");
            continue;
        }
    }
    else
    {
        printf("wrong answer \n");
    }
}

return y;
}

int main()
{
int y = yRechner();
printf("y = %d\n", y);

return 0;
}