I have a table looks like below where day, order_id, and order_type are stored.
select day, order_id, order_type
from sample_table
day | order_id | order_type |
---|---|---|
2021-03-01 | 1 | offline |
2021-03-01 | 2 | offline |
2021-03-01 | 3 | online |
2021-03-01 | 4 | online |
2021-03-01 | 5 | offline |
2021-03-01 | 6 | offline |
2021-03-02 | 7 | online |
2021-03-02 | 8 | online |
2021-03-02 | 9 | offline |
2021-03-02 | 10 | offline |
2021-03-03 | 11 | offline |
2021-03-03 | 12 | offline |
Below is desired output:
day | total_order | num_offline_order | num_online_order |
---|---|---|---|
2021-03-01 | 6 | 4 | 2 |
2021-03-02 | 4 | 2 | 2 |
2021-03-03 | 2 | 2 | 0 |
Does anybody know how to query to get the desired output?
You need to pivot the data. A simple way to implement conditional aggregation in Vertica uses ::
:
select day, count(*) as total_order,
sum( (order_type = 'online')::int ) as num_online,
sum( (order_type = 'offline')::int ) as num_offline
from t
group by day;
Use case
and sum
:
select day,
count(1) as total_order
sum(case when order_type='offline' then 1 end) as num_offline_order,
sum(case when order_type='online' then 1 end) as num_online_order
from sample_table
group by day
order by day
you can also use count
to aggregate values that are not null
select
day,
count(*) as total_order,
count(case when order_type='offline' then 1 else null end) as offline_orders,
count(case when order_type='online' then 1 else null end) as online_orders
from sample_table
group by day
order by day;
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