I get compile error ("no match for operator==") when using std::equal
and my classes are define in separate namespaces (proper operators are defined).
This is my working example using std::equal
but without namespace and there is no compile error
#include <vector>
#include <algorithm>
struct K {
int a;
};
struct V {
int b;
};
inline bool operator== (const K& lhs, const V& rhs) {
return lhs.a == rhs.b;
}
inline bool operator== (
const std::vector<K>& lhs, const std::vector<V>& rhs) {
return std::equal(lhs.begin(), lhs.end(), rhs.begin());
}
But when I use namespace for my classes there is "no match operator" error
#include <vector>
#include <algorithm>
namespace nk {
struct K {
int a;
};
}
namespace nv {
struct V {
int b;
};
}
inline bool operator== (const nk::K& lhs, const nv::V& rhs) {
return lhs.a == rhs.b;
}
inline bool operator== (const std::vector<nk::K>& lhs, const std::vector<nv::V>& rhs) {
return std::equal(lhs.begin(), lhs.end(), rhs.begin());
}
/opt/compiler-explorer/gcc-10.2.0/include/c++/10.2.0/bits/stl_algobase.h:1107:22: error: no match for 'operator==' (operand types are 'const nk::K' and 'const nv::V')
Also there is no error when std::equal
replaced with simple loop (compare operators work well in this case):
inline bool operator== (const std::vector<nk::K>& lhs, const std::vector<nv::V>& rhs) {
if (lhs.size() != rhs.size()) {
return false;
}
for(std::size_t i=0; i<lhs.size(); i++) {
if (!(lhs[i]==rhs[i])) {
return false;
}
}
return true;
}
Codes are tested with Compiler Explorer and GCC 10.0.2 (I've also tested other GCC versions)
The problem is that the library like std::equal
can't find the operator==
defined in global scope.
You can move operator==
into either the namespace where K
or V
is defined to validate ADL . (PS your 1st code snippet works because of ADL too.)
Eg
namespace nk {
struct K {
int a;
};
}
namespace nv {
struct V {
int b;
};
inline bool operator== (const nk::K& lhs, const nv::V& rhs) {
return lhs.a == rhs.b;
}
}
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