REGEX Python right quotation mark

Question

At first this is my REGEX until now

(``|,,|")([^"|^'{2}|`{2}|^,{2}]*)(''|``|")

I think that negation in the secound group that I setted isnt working correctly. I seperated all my negations like you can see, I dont know if that can work.

This should for example find this sentence

``Some question is here ,some text here''

but not this one

``Some question is here ,,some text here''

Im already trying to find the solution for hours but im new at Regex and I couldnt find the solution. Thanks in advance for any help.

Answer 1

You can use

^(``|,,|")((?:(?!"|'{2}|`{2}|,{2}).)*)(''|``|")$

See the regex demo

Details :

• ^ - start of string/line
• (``|,,|") - two backticjks, commas or a double quotation mark
• ((?:(?,"|'{2}|`{2}|.{2}).)*) - any single char other than line break chars, as many as possible, that is not a " and does not start a '' , two backticks, or ,, char sequence
• (''|``|") - '' , two backticks, or a "
• $ - end of string/line.

See a Python demo :

import re
rx = r"""^(``|,,|")((?:(?!"|'{2}|`{2}|,{2}).)*)(''|``|")$"""
texts = ["``Some question is here ,some text here''", "``Some question is here ,,some text here''"]
for text in texts:
    m = re.search(rx, text)
    if m:
        print(f"MATCHED: {text}")