Pandas searching for list in Dataframe column

Question

I have a dataframe with lots of columns and one of them is a list of IDs.

eg

   |  IDs        |  IPs     |  ...
 1 |[12, 55, 15] |  123...  |  ...
 2 |[12]         |  222...  |  ...
 3 |[10, 11, 5]  |  234...  |  ...  
 4 |[12, 55, 15] |  123...  |  ...
 5 |[12, 55, 15] |  123...  |  ...

I have another list

l1 = [12 , 15, 55] 

The results I want

   |  IDs        |  IPs     |  ...
 1 |[12, 55, 15] |  123...  |  ...
 4 |[12, 55, 15] |  123...  |  ...
 5 |[12, 55, 15] |  123...  |  ...

I have tried using .isin , .query , and tried to other solutions online but none of them worked for me. The result I gotten are empty dataframes and

0          False
1          False
2          False
3          False
4          False

edit: The order is not important. I just want the numbers in the list to be in the result.

Answer 1

You can compare tuple s if order is important:

import ast

#if necessary convert strings to lists
df['IDs'] = df['IDs'].apply(ast.literal_eval)

mask = df['IDs'].apply(tuple).eq(tuple(l1))

Answer 2

Use apply lambda if order is important.

df.IDs.apply(lambda x: x == l1)

Answer 3

This a solution I have found:

Edit: Actually really close solution from Hamza usman ghani's one. What is wrong exactly with his?

import pandas as pd

df = pd.DataFrame(data={"column":[[12, 55, 15],[12, 55, 15],[12],[12, 55, 15]],"value":[5,5,1,5]})
print(df["column"].apply(lambda x : x==[12,55,15])) # prints {0,True ... }
print(df[df["column"].apply(lambda x : x==[12,55,15])]) # prints what you want