I am developing an online voting system for my final year college project. The multi threading class gives a user 15 seconds to vote. It accepts a timestamp cookie and compares it to the current time.
class MonitorThread(threading.Thread):
def __init__(self, timecookie):
threading.Thread.__init__(self)
self.timecookie = timecookie
def run(self):
try:
while 1:
timenow = datetime.timestamp(datetime.now())
if timenow - int(float(self.timecookie)) < 15:
continue
else:
return redirect(url_for('index'))
sleep(0.1)
except KeyboardInterrupt:
GPIO.cleanup()
The videostream route runs the user's webcam to capture images for face verification and also runs an instance of the multi threading class.
@ app.route('/videostream')
def videostream():
video_stream = VideoCamera()
timecookie = getcookie('time')
MonitorThread(timecookie).start()
return Response(gen(video_stream), mimetype='multipart/x-mixed-replace; boundary=frame')
This results in an error:
Traceback (most recent call last):
File "/usr/lib/python3.8/threading.py", line 932, in _bootstrap_inner
self.run()
File "/home/abhishek/Documents/sem8/project/myfinalyear/app/app.py", line 48, in run
return redirect(url_for('index'))
File "/home/abhishek/Documents/sem8/project/myfinalyear/env/lib/python3.8/site-packages/flask/helpers.py", line 306, in url_for
raise RuntimeError(
RuntimeError: Attempted to generate a URL without the application context being pushed. This has to be executed when application context is available.
I want to end the voting process as soon as the time is up. Please suggest ideas.
Have you tried wrapping it with a with
statement?
with app.app_context():
If it still doesn't work, you can try setting a SERVER_NAME
configuration, as written in the documentation :
If set, url_for can generate external URLs with only an application context instead of a request context
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.