I have a problem, I have my class and my minmax function coded as below
template<typename T>
class Processus {
public:
typedef pair<double, T> state;
typedef vector<state> result_type;
Processus(int n = 0) : v(n+1)
{
Schedule w(n);
auto i_w = w.begin();
for (auto it = v.begin(); it != v.end(); ++it, ++i_w) it->first = *i_w;
};
Processus(const Schedule& w) : v(w.size()) {
auto i_w = w.begin();
for (auto it = v.begin(); it != v.end(); ++it, ++i_w) it->first = *i_w;
}
~Processus() {};
virtual result_type operator()() = 0;
auto begin() const { return v.begin(); };
auto end() const { return v.end(); };
pair<T, T> minmax() const;
protected:
vector<state> v;
};
pair<vector<double>, vector<double>> minmax(const vector<double>& v1, const vector<double> v2){
pair<vector<double>, vector<double>> cur(v1, v2);
auto i_min = cur.first.begin(), i_max = cur.second.begin();
for (auto it = v1.begin(), it2 = v2.begin(); it != v1.end(); ++it, ++it2, ++i_min, ++i_max) {
*i_min = ::min(*it, *it2);
*i_max = ::max(*it, *it2);
}
return cur;
}
template<>
inline pair<vector<double>, vector<double>> Processus<vector<double>>::minmax() const {
pair<vector<double>, vector<double>> cur(begin()->second, begin()->second);
for (auto it = begin()+1; it != end(); ++it) {
cur.first = minmax(it->second,cur.first).first;
cur.second = it->second.minmax(cur.second).second;
};
return cur;
};
However, I get the error:
error: no matching function for call to 'Processus<std::vector<double> > >::minmax(const std::vector<double>&, std::vector<double>&) const'
Which correspond to this line:
cur.first = minmax(it->second,cur.first).first;
Inside of Processus::minmax()
, your intent is to call your standalone 2-parameter minmax()
function. However, from the error message, it is clear that the compiler is trying to call Processus::minmax()
recursively instead, which does not work since Processus::minmax()
does not take in any parameters.
To call the standalone function of the same name, prefix the call with the ::
scope operator:
cur.first = ::minmax(it->second,cur.first).first;
Otherwise, rename the standalone function to something more unique.
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